AP EAPCET 19-Aug-2021 Shift 2 Paper

Equation of line passing through
A(4,7) and B(−7,8) is

x−4

−11

=

y−7

1

Or x+11y−81=0 ...(i)
Mid-point of AB=(

−3

2

,

15

2

)
Let equation of line perpendicular to line (i) is
11x−y+C=0
This line passes through (

−3

2

,

15

2

)
∴11×

−3

2

−

15

2

+C=0
⇒ C = 24
∴ Required equation of perpendicular bisector of AB is
11x−y+24=0