AP EAPCET 19-Aug-2021 Shift 2 Paper

a, b, c are unit vectors
⇒ |a| = |b| = |c| = 1
∵ a . b = 0 and a . c = 0
⇒ a ⊥ b and a ⊥ c
Angle between b and c is

π

3

∴ b × c = |b| . |c| sin

π

3

.

^

a

‌‌‌‌‌ [∵ a is perpendicular to b and c and

^

a

=1]
=1.1.

√3

2

=

√3

2

Now, [abc]2=[a.(b×c)]2
=|a.

√3

2

|2=|a|2.(

√3

2

)2
=1.

3

4

=

3

4