Find the emf of the following cell reaction, given \E^\circ_{\Cr^{3+} \/ \Cr^{2+}} =-0.72 {\V} and \E^\circ_{{\Fe}^{2+} \/ {\Fe}} = -0.42 {\V} at 25^\circ{\C} is {\Cr}|{\Cr}^{3+}(0.1 {\M}) \| {\Fe}^{2+}(0.1 {\M})| {\Fe}

AP EAPCET 19-Aug-2021 Shift 2 Paper

Section: Chemistry

Question : 150 of 160

Marks: +1, -0

Find the emf of the following cell reaction, given E°Cr3+∕Cr2+=−0.72V and E°Fe2+∕Fe= −0.42V at 25°C is Cr|Cr3+(0.1M)|Fe2+(0.1M)|Fe

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