AP EAPCET 19-Aug-2021 Shift 2 Paper
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Question : 135 of 160
Marks:
+1,
-0
Using the data provided, find the value of equilibrium constant for the following reaction at 298 K and 1 atm pressure. NO ( g ) +
O 2 ( g ) ⇌ NO 2 ( g )
Δ f H 0 ( NO ( g ) ) = 90.4 kJ mol − 1
Δ f H 0 ( NO 2 ( g ) ) = 32.48 kJ mol − 1
Δ S 0 @ 298 K = − 70.8 JK − 1 mol − 1
antilog ( 0.50 ) = 3162
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