AP EAPCET 19-Aug-2021 Shift 2 Paper

Given, maximum amplitude of modulated signal,
Vmax=15V=Vm+Vc ...(i)
Minimum amplitude of modulated signal,
Vmin=5V=Vm−Vi ...(ii)
where, Vc,Vm are carries wave and modulated wave voltage.
Now, from Eqs. (i) and (ii), we get
20=2Vm
⇒Vm=10V