AP EAPCET 19-Aug-2021 Shift 2 Paper

Given, electric potential, V=100V
Since, λ=

h

p

=

h

mc

=

h

√2mE

=

h

√2meV

where, λ is wavelength,
h is Planck's constant i.e. 6.63×10−34Js−1,
m is mass of photon, c is speed and e is charge on proton
∴λ=

6.63×10−34

√2×1.67×10−27×1.6×10−19×200

=0.203×10−11m
=2.03‌pm
It is near to 2.86‌pm.