AP EAPCET 19-Aug-2021 Shift 1 Paper

Given, expansion of spring, Δx=0.4m
Mass suspended in case I (m1) and case II (m2) is 0.6‌kg and 255g, respectively.
Acceleration due to gravity g=10ms−2
Since, force F=mg=kΔx
∴ Spring constant k=

mg

Δx

⇒k=

m1g

Δx1

=

0.6×10

0.4

=15

N

m

and time period, T=2π√

m

k

T2=2π√

m2

k

T2=2π√

0.255

15

=2π√

255

15×103

=2π√0.017=0.82s