AP EAPCET 19-Aug-2021 Shift 1 Paper

Given, mass of ball 1,m1=2‌kg
Mass of ball 2,m2=3‌kg
u1=36‌km∕h=36×

5

18

m∕s=10m∕s
u2=0
After collision, the two balls will stick together and their combined velocity be v.
Now, by using law of conservation of momentum,
m1u1+m2u2=(m1+m2)v
⇒v=

2×10+3×0

5

=4ms−1
∴ Energy loss = Energy before collision (E2)−Energy‌after‌collision(E1)
=(

1

2

m1u12+

1

2

m2u22)−

1

2

(m1+m2)v2
=(

1

2

×2×102+

1

2

×3×02)−

1

2

(2+3)42
=

1

2

×2×100−

1

2

×5×16
=100−40=60J