AP EAPCET 19-Aug-2021 Shift 1 Paper

Given, applied force, F=40N
Horizontal component of force, Fx=20√3
and θ be the angle of force from horizontal X-axis.
According to given diagram,
The component of F along X-axis will be Fx=F‌cos‌θ
⇒20√3=40‌cos‌θ
⇒

√3

2

=cos‌θ
∴θ=cos−1(

√3

2

)=30°
And the component of F along Y-axis
Fy=F‌sin‌θ
=F‌sin‌30°
=40×

1

2

=20N