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Question : 78 of 160
Marks:
+1,
-0
Solution:
Let
I=∫24(|x−2|+|x−3|)dx ∵x−a={| x−a, | x≥a |
| −(x−a), | x<a |
∴I=∫24|x−2|dx+∫23|x−3|dx+∫34|x−3|dx
=∫24(x−2)dx−∫23(x−3)dx+∫34(x−3)dx
=|2+−4−4+|=[2+9−8]=3
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