If the function f(x), defined below is continuous in the interval [0, \\pi], then _______ f(x)=\\begin{array}{c}x+a \\sqrt{2\end{array}(\sin x),{,} , 0 \\leq x

Correct Answer is : a=π6,b=−π12

a=\frac{\\pi}{6}, b=\frac{\\pi}{12}

a=\frac{-\\pi}{6}, b=\frac{\\pi}{12}

a=\frac{-\\pi}{6}, b=\frac{-\\pi}{12}

a=\frac{\\pi}{6}, b=\frac{-\\pi}{12}

AP EAPCET 19-Aug-2021 Shift 1 Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

If the function f(x), defined below is continuous in the interval [0,π], then _______

f(x)={

x+a√2(sin‌x)

0≤x<

2x(cot‌x)+b

≤x≤

a(cos‌2‌x)−b(sin‌x)

<x≤π

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