If \overline{ {\a}}= {\t} \overline{ {\b}} where {\t}< 0 is a scalar, then

Correct Answer is : a,b are unlike vectors and either |a|≥|b| or |a|<|b|

\overline{ {\a}}, \overline{ {\b}} are like vectors and |\overline{ {\a}}|>|\overline{ {\b}}|

\overline{ {\a}}, \overline{ {\b}} are unlike vectors and |\overline{ {\a}}|>|\overline{ {\b}}|

\overline{ {\a}}, \overline{ {\b}} are like vectors and |\overline{ {\a}}|< |\overline{ {\b}}|

\overline{ {\a}}, \overline{ {\b}} are unlike vectors and either |\overline{ {\a}}| \geq|\overline{ {\b}}| or |\overline{ {\a}}|< |\overline{ {\b}}|

AP EAPCET 18th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 29 of 160

Marks: +1, -0

If a=tb where t<0 is a scalar, then

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