\int {x+1}/{\sqrt{x^2+x+1}} {\d} x= [AP EAPCET 18 May 2024 Shift 1]

Correct Answer is : √x2+x+1+12 sinh−1(2x+1√3)+c

\frac{1}{2} \sqrt{x^2+x+1}+\frac{1}{2} \cosh ^{-1} ( {x+2}/{\sqrt{3}}) + {\c}

\frac{1}{2} \sqrt{x^2+x+1}+ {2}/{\sqrt{3}} {\Tan}^{-1} ( {2 x+1}/{\sqrt{3}}) + {\c}

\sqrt{x^2+x+1}+ {2}/{\sqrt{3}} \log {| x^2+x+1 |}+ {\c}

\sqrt{x^2+x+1}+\frac{1}{2} \sinh ^{-1} ( {2 x+1}/{\sqrt{3}}) + {\c}

AP EAPCET 18 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 70 of 160

Marks: +1, -0

∫‌

x+1

√x2+x+1

dx=

[AP EAPCET 18 May 2024 Shift 1]

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