AP EAPCET 18 May 2024 Shift 1 Solved Paper

The magnetic energy stored in an inductor is given by the formula:
U=‌

1

2

LI2
Where:
U is the energy stored,
L is the inductance,
I is the current through the inductor.
In this case, the current increases from I1=2A to I2=3A.
Calculating the initial energy stored U1 when the current is I1 :
U1=‌

1

2

LI12=‌

1

2

×L×4=2L
Calculating the energy stored U2 when the current is I2 :
U2=‌

1

2

LI22=‌

1

2

×L×9=4.5L
The increase in energy stored, ∆U, is:
∆U=U2−U1=4.5L−2L=2.5L
To find the percentage increase in energy stored:
Percentage Increase =‌

∆U

U1

×100%=‌

2.5L

2L

×100%=125%