For a positive real number \lambda, if the vector \overline{ {\a}}=\lambda \overline{\ov{i}}-5 \overline{ {\j}}+6 \overline{ {\k}} satisfies the equation [\overline{ {\i}} \times(\overline{ {\a}} \times \overline{ {\i}})+\overline{ {\j}} \times(\overline{ {\a}} \times \overline{ {\j}})+\overline{ {\k}} \times(\overline{ {\a}} \times \overline{ {\k}})]^2=440, then \lambda=

AP EAPCET 17th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 31 of 160

Marks: +1, -0

For a positive real number λ, if the vector a=λi−5j+6k satisfies the equation

[i×(a×i)+j×(a×j)+k×(a×k)]2=440, then λ=

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