AP EAPCET 17th May 2023 Shift 2 Solved Paper

Section: Mathematics

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Question : 10 of 160

Marks: +1, -0

For x∈ℝ, the minimum value of ‌

x2+2x+5

x2+4x+10

is

‌
1
2
‌
4
3
2‌
3
4
−‌
1
2

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