AP EAPCET 17th May 2023 Shift 1 Solved Paper

Section: Physics

Question : 84 of 160

Marks: +1, -0

At any instant ' t ' the vertical distance ' Y ' and horizontal distance ' X ' of a projectile are given by 2Y=6t−gt2 and X=4t. The initial velocity of projectile is
( X and Y are in metre and t is in second)

3ms−1
4ms−1
5ms−1
6ms−1

Validate

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