Let [t] represents the greatest integer not exceeding t and C=1-2 e^2. If the function f(x)= \\begin{array}{cccc}[e^x] \text{ & } & x&lt\ 0 \ a e^x+[x-2]\text{ & } & \\\0 \leq x&lt\ 2 \ { [e^{-x\end{array}] -C}\text{,},x \geq 2 is continuous at {\x}=2, then {\f}( {\x}) is discontinuous at

{\x}=0, {\x}=1 and {\x}=\frac{1}{2}

AP EAPCET 17th May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 60 of 160

Marks: +1, -0

Let [t] represents the greatest integer not exceeding t and C=1−2e2.
If the function f(x)={

is continuous at x=2, then f(x) is discontinuous at

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