If \overline{ {\OA}}=2 \overline{ {\i}}-\overline{ {\j}}+\overline{ {\k}}, \overline{ {\OB}}=3 \overline{ {\i}}-\overline{ {\k}} and \overline{ {\OC}}=2 \overline{ {\j}}+3 \overline{ {\k}} are the position vectors of the points {\A}, {\B} and {\C}, then a unit vector perpendicular to the plane containing {\A}, {\B} and {\C} is

Correct Answer is : 8i+2j+5k√93

{8 \overline{ {\i}}-4 \overline{ {\j}}+2 \overline{ {\k}}}/{2 \sqrt{21}}

{6 \overline{ {\i}}+2 \overline{ {\j}}+3 \overline{ {\k}}}/{7}

{9 \overline{i}+2 \overline{j}+6 \overline{k}}/{11}

{8 \overline{ {\i}}+2 \overline{ {\j}}+5 \overline{ {\k}}}/{\sqrt{93}}

AP EAPCET 17th May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 32 of 160

Marks: +1, -0

If OA=2i−j+k,OB=3i−k and OC=2j+3k are the position vectors of the points A,B and C, then a unit vector perpendicular to the plane containing A,B and C is

‌
8i−4j+2k
2√21
‌
6i+2j+3k
7
‌
9i+2j+6k
11
‌
8i+2j+5k
√93

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