\int_{0}^{\frac{\pi}{4}} \frac{\cos ^2 x}{\cos ^2 x+4 \sin ^2 x} \dx=

Correct Answer is : −π12+23Tan−12

\frac{\pi}{4}+\frac{2}{3} {\Tan}^{-1} 2

-\frac{\pi}{3}-\frac{2}{3} {\Tan}^{-1} 3

-\frac{\pi}{12}+\frac{2}{3} {\Tan}^{-1} 2

\frac{\pi}{6}-\frac{2}{3} {\Tan}^{-1} 4

AP EAPCET 15th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

‌

∫

‌

cos2x

cos2x+4sin‌2x

‌dx=

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