If {\f}( {\x}+a y)+ {\g}( {\x}- {\ay})=0, then {\a} { {\dy}}/{ {\dx}}=

Correct Answer is : f′(x+ay)+g′(x−ay)g′(x−ay)−f′(x+ay)

{f^{'}(x-a y)+g^{'}(x+a y)}/{g^{'}(x+a y)-f^{'}(x-a y)}

{f^{'}(x+a y)+g^{'}(x-a y)}/{g^{'}(x-a y)-f^{'}(x+a y)}

{f^{'}(x+a y) g^{'}(x-a y)}/{f^{'}(x+a y)+g^{'}(x-a y)}

{f^{'}(x+a y)+g^{'}(x-a y)}/{f^{'}(x+a y) g^{'}(x-a y)}

AP EAPCET 15th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

If f(x+ay)+g(x−ay)=0, then a‌

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