The diagonals {\AC} and {\BD} of a rhombus {\ABCD} intersect at the point (3,4). If {\BD}=2 \sqrt{2}, {\A}=(1,2), {\B}=(\alpha, \beta), {\D}=(\gamma, \delta) and \alpha< \delta< \gamma< \beta, then \beta+\gamma-\delta=

AP EAPCET 15th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 43 of 160

Marks: +1, -0

The diagonals AC and BD of a rhombus ABCD intersect at the point (3,4). If BD=2√2,A=(1,2),B=(α,β),D=(γ,δ) and α<δ<γ<β, then β+γ−δ=

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