Masses {m}(\frac{1}{2}) \frac{1}{| {N}|} are placed at {x}= {N} on the {x}-axis where {N}=-1,0,1,2, . . . \infty. If the total mass of the system is M, then the position of the centre of mass of the system is

(\frac{7}{4} { {m}}/{ {M}}, 0,0)

(\frac{5}{4} { {m}}/{ {M}}, 0,0)

(\frac{3}{4} { {m}}/{ {M}}, 0,0)

(\frac{1}{4} { {m}}/{ {M}}, 0,0)

AP EAPCET 12 July 2022 Shift 2 Paper

Question : 89 of 160

Marks: +1, -0

Masses m(‌

)‌‌‌

|N|

are placed at x=N on the x-axis where N=−1,0,1,2,...∞. If the total mass of the system is M, then the position of the centre of mass of the system is

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