Consider a radioactive isotope { }_{92} {U}^{238} decays into { }_{52} {Pb}^{206} in a series by emission of n_\alpha number of alpha particles and n_\beta number of beta particles. Then the values of n_\alpha and n_\beta ?

Correct Answer is : nα=8,nβ=6

AP EAPCET 11 July 2022 Shift 2 Paper

Question : 118 of 160

Marks: +1, -0

Consider a radioactive isotope ‌92U238 decays into ‌52Pb206 in a series by emission of nα number of alpha particles and nβ number of beta particles. Then the values of nα and nβ ?

nα=8,nβ=8
nα=6,nβ=6
nα=8,nβ=6
nα=6,nβ=8

Validate

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