The density of a gas is 1 molecules {cm}^{-3}. If the molecular diameter is 1 \times 10^{-8} {cm} then the mean free path of the molecules is

Correct Answer is : 1√2π×1014m

\frac{1}\sqrt{2} \pi} \times 10^{14} {m}

\frac{1}{2 \pi} \times 10^{13} {m}

\frac{1}\sqrt{6} \pi} \times 10^{14} {m}

\frac{1}\sqrt{2} \pi} \times 10^{13} {m}

AP EAPCET 11 July 2022 Shift 2 Paper

Question : 100 of 160

Marks: +1, -0

The density of a gas is 1 molecules cm−3. If the molecular diameter is 1×10−8cm then the mean free path of the molecules is

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