A block is executing simple harmonic motion and its position is given by x=A \cos (\omega t+\phi). At time t=0, the ratio of the kinetic energy to the potential energy is \frac{1}{3}. The magnitude of the phase angle \phi is

AP EAPCET 11 July 2022 Shift 1 Paper

Question : 92 of 160

Marks: +1, -0

A block is executing simple harmonic motion and its position is given by x=A‌cos(ωt+φ). At time t=0, the ratio of the kinetic energy to the potential energy is ‌

. The magnitude of the phase angle φ is

60∘
30∘
tan−1(‌
2
3
)
tan−1(‌
3
2
)

Validate

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