Calculate ∆_{r} H^{0} for the reaction {A}^{+}( {aq})+ {B}^{-}( {aq}) \to {AB}( {s}) at 25^{\circ} {C} ∆_{f} H^{0}(A^{+}, a q)=200 {kJ} {mol}^{-1} ∆_{f} H^{0}(B^{-}, a q)=-300 {kJ} {mol}^{-1} ∆_{f} H^{0}(A^{+}, g)=-150 {kJ} {mol}^{-1} ∆_{f} H^{0}(A B, s)=-250 {kJ} {mol}^{-1} ∆_{f} H^{0}(A B, g)=+130 {kJ} {mol}

Correct Answer is : −150kJmolm−1

AP EAPCET 11 July 2022 Shift 1 Paper

Question : 130 of 160

Marks: +1, -0

Calculate ∆rH0 for the reaction A+(aq)+B−(aq)→AB(s) at 25∘C
∆fH0(A+,aq)=200‌kJmol−1
∆fH0(B−,aq)=−300‌kJmol−1
∆fH0(A+,g)=−150‌kJmol−1
∆fH0(AB,s)=−250‌kJmol−1
∆fH0(AB,g)=+130‌kJmol

150‌kJmol−1
−150‌kJmolm−1
0‌kJmol−1
+130‌kJmol−1

Validate

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