(\sqrt{x+\sqrt{12 x-36}+\sqrt{x-\sqrt{12 x-36}) d x=

Correct Answer is : {43(x−3)3/2+C if x>62√3x+C if 3≤x≤6.

\frac{4(x-3)^{3 \/ 2}}{2}+C, \forall x

\\begin{array}{c}\\\{4\end\frac{array}{3}(x-3)^{3 {/} 2}+C, \text{ if } , x>6 ; 2 \sqrt{3} x+C , \text{ if } , 3 \leq x \leq 6.

\\begin{array}{c}\\\{4\end\frac{array}{3}(x-3)^{3 {/} 2}+C,\text{ if } , 3 \leq x \leq 6 ; 2 \sqrt{3} x+C , \text{ if } , x>6.

AP EAPCET 08-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

(√x+√12x−36+√x−√12x−36)dx=

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