The circle x^{2}+y^{2}-4 x-8 y+16=0 rolls up along the tangent drawn to it at (2+\sqrt{3}, 3) by 2 units. The equation of the circle in the new position is

Correct Answer is : x2+y2−6x−2(4+√3)y+(24+8√3)=0

x^{2}+y^{2}-6 x-2(4+\sqrt{3}) y+(24+8 \sqrt{3})=0

x^{2}+y^{2}-6 x+2(4+\sqrt{3}) y+(24+8 \sqrt{3})=0

x^{2}+y^{2}+6 x-2(4+\sqrt{3}) y+(24+8 \sqrt{3})=0

x^{2}+y^{2}+6 x+2(4+\sqrt{3}) y+(24+8 \sqrt{3})=0

AP EAPCET 08-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 50 of 160

Marks: +1, -0

The circle x2+y2−4x−8y+16=0 rolls up along the tangent drawn to it at (2+√3,3) by 2 units. The equation of the circle in the new position is

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