AP EAPCET 08-Jul-2022 Shift 2 Paper

Given, A=[

1	−1	0	−2
−4	4	0	8
−2	1	2	4

]
Now we apply elementary transformations,
Applying R3→R3+2R1 and R2→R2+4R1
A=[

1	−1	0	−2
0	0	0	0
0	−1	2	0

]
Applying R2↔R3,
A=[

1	−1	0	−2
0	−1	2	0
0	0	0	0

]
Matrix A is in row echelon form.
Number of non-zero rows =2
hence, rank of matrix A=2