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Question : 20 of 160
Marks:
+1,
-0
Solution:
Given,
1−cot‌23°= ⇒x=(1−cot‌23°)(1−cot‌22°) ⇒x=| (sin‌23°−cos‌23°) |
| sin‌23° |
×| (sin‌22°−cos‌22°) |
| sin‌22° |
⇒(sin‌23°.sin‌22°+cos‌23°.cos‌22°) ⇒x=| −(sin‌23°‌cos‌22°+cos‌23°‌sin‌22°) |
| sin‌23°.sin‌22° |
⇒x+| −(sin‌23°−22°)−sin(23°+22°) |
| sin‌23°.sin‌22° |
⇒x=| 2(cos‌1°−sin‌45°) |
| 2‌sin‌23°‌sin‌22° |
=| 2(cos‌1°−) |
| (cos‌1°−cos‌45°) |
⇒| 2(cos‌1°−) |
| cos‌1°− |
=2
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