A block of 10 {kg} mass is connected to the top of a frictionless inclined plane of inclination 45^{\circ} by a spring of negligible mass, unstretched length 0.8 {m} and spring constant 100 \sqrt{2} {Nm}^{-1}. Then the distance of the block from the top along the incline in the equilibrium position is (acceleration due to gravity =10 {m} {s}^{-2} )

AP EAPCET 08-Jul-2022 Shift 1 Paper

Section: Physics

Question : 91 of 160

Marks: +1, -0

A block of 10kg mass is connected to the top of a frictionless inclined plane of inclination 45∘ by a spring of negligible mass, unstretched length 0.8m and spring constant 100√2Nm−1. Then the distance of the block from the top along the incline in the equilibrium position is
(acceleration due to gravity =10ms−2 )

0.9m
1.1m
1.3m
1.5m

Validate

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