AP EAPCET 08-Jul-2022 Shift 1 Paper

To find height of building we have to analyze vertical motion of ball.
Now in given case,
Initial velocity, uy=usinθ
⇒uy=15×sin‌30∘=15×

1

2

=7.5m∕ s

Acceleration, ay=−g=−10m∕ s−
Time to reach the ground =3 s.
Now using h=uyt+

1

2

ayt2, we get
h=7.5×3−

1

2

×10×32
=225−45=−22.5m
So, height of building =22.5m