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Question : 76 of 160
Marks:
+1,
-0
Solution:
Let
I=[√x+2√x−1+√x−2√x−1]‌dx =[√x−1+1+2√x−1+√x−1+1−2√x−1]‌dx =[√√(x−1+1)2+√(√x−1−1)2]‌dx =[√x−1+1+√x−1−1]‌dx =2‌√x−1‌dx =2‌(x−1)‌‌dx =2×[(x−1)3∕2]25 =[43∕2−13∕2] =[8−1] =
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