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Question : 29 of 160
Marks:
+1,
-0
Solution:
D is mid - point od BC
Coordinate of
D is
(,,,−) ⇒
(,,) AD=√(−2)2+(−1)2+(−−2)2 =√(√3−22+(√3−2)2+(−√6−4)2 =√3+4−4√3+3+4−4√3+6+16+8√6 =√36−8√3+8√6 =√9−2√3+2√6 Compare it
λ√9−3√3+2√6 , we get
λ=1
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