AP EAPCET 08-Jul-2022 Shift 1 Paper

From a deck of 52 cards, one ace can be selected in ‌4C1=4 ways and the remaining 4 cards can be selected from the remaining 48 non-ace cards in ‌48C4 ways.
∴ The required number of 5 cards combination
=4×48C4
=

4×48×47×46×45

1×2×3×4

=4×2×47×45=778320