AP EAPCET 07-Jul-2022 Shift 2 Paper

The gievn situation is shown below

From above figure we can observe that velocity vector (tangential to circle) can be resolved into horizontal (v‌cos‌

θ

2

) and vertical (v‌sin‌

θ

2

)
components.
As, particle is executing uniform circular motion, magnitudes of components remains same but direction of vertical component is reversed.
So, Initial velocity
v1=v‌cos‌

θ

2

‌

^

i

+v‌sin‌

θ

2

‌

^

j

and
final velocity, v2=v‌cos‌

θ

2

‌

^

i

−v‌sin‌

θ

2

‌

^

j

Change‌in‌velocity=final‌velocity−Initial‌velocity
=v2−v1
=(v‌cos‌

θ

2

‌

^

i

−v‌sin‌

θ

2

‌

^

j

)−(v‌cos‌

θ

2

‌

^

i

+v‌sin‌

θ

2

‌

^

j

)
=−2v‌sin‌

θ

2

‌

^

j

Magnitude of change of velocity will be
|∆v|=|v2−v1|
=2v‌sin‌

θ

2

‌

^

j