\int \sqrt{x+\sqrt{x^{2}+2}} d x=

Correct Answer is : (x+√x2+2)2−63√x+√x2+2+C

\frac{3}{2}(x+\sqrt{x+2})^{3 {/}2}-2(x+\sqrt{x^{2}+2})^{1{/}4}+C

\frac{1}{3}(x+\sqrt{x^{2}+2})^{3{/}2}-2(x+\sqrt{x^{2}+2})^{1{/}4}+C

(x+\sqrt{x^{2}+2})^{-3 {/}2}-2(x+\sqrt{x^{2}+2})^{-1 {/} 2}+C

{(x+\sqrt{x^{2}+2})^{2}-6}/{3 \sqrt{x+\sqrt{x^{2}+2}}}+C

AP EAPCET 07-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫√x+√x2+2dx=

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