If (1,2) is the focus, x+2 y=0 is the directrix and \sqrt{2} is the eccentricity of a hyperbola then the equation of the hyperbola is

Correct Answer is : 3x2−8xy−3y2−10x−20y+25=0

3 x^{2}-8 x y-3 y^{2}-10 x-20 y+25=0

3 x^{2}-8 x y-3 y^{2}+10 x-20 y-25=0

AP EAPCET 07-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 54 of 160

Marks: +1, -0

If (1,2) is the focus, x+2y=0 is the directrix and √2 is the eccentricity of a hyperbola then the equation of the hyperbola is

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