AP EAPCET 07-Jul-2022 Shift 2 Paper

Line is normal to circle x2+y2−4y−6=0
∴ It passes through Centre (0,2).
Let m be slope of line.
∴ Equation of line is y−2=mx
⇒mx−y+2=0
This line is tangent to x2+y2−2x−3=0
Centre is (1,0), radius is 2
∴2=|

m+2

√1+m2

|
⇒4(1+m2)=(m+2)2
∴3m2−4m=0
⇒m=0
or m=

4

3

∴ Line can be y=2
or 4x−3y+6=0