{x^{4}}/{(x^{2}+1)(x^{2}+3)}=

Correct Answer is : 1+Ax+Bx2+1+Cx+Dx2+3 for some A,B,C,DE R

\frac{A x+B}{x^{2}+1}+\frac{C x+D}{x^{2}+3} for some A.B.C.DER \\{0\}

\frac{A x+B}{x^{2}+1}+\frac{C x}{x^{2}+1} for some A,B, C \in R \ \{0\}

\frac{A x}{x^{2}+1}+\frac{B x}{x^{2}+3} for some A, B \in R \ \{0\}

1+\frac{A x+B}{x^{2}+1}+\frac{C x+D}{x^{2}+3} for some A,B,C,DE R

AP EAPCET 07-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 19 of 160

Marks: +1, -0

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(x2+1)(x2+3)

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