Let f: R \to R be defined by f(x)=2 x+3. If \alpha. \beta are the roots of the equation {f}( {x}^{2})-2 {f}(\frac{x}{2})-1=0 then \alpha^{2}+\beta^{2}=

AP EAPCET 07-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 1 of 160

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Let f:R→R be defined by f(x)=2x+3. If α. β are the roots of the equation f(x2)−2f(‌

)−1=0 then α2+β2=

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