\int_{-\pi}^{\pi} {\cos ^{2022} x}/{1+(2022)^{x}} d x=

Correct Answer is : (2022)!22022((1011)!)2π

{(2022) !}/{2^{2022}((1011) !)^{2}} \pi

({ }^{2022} C_{1011}) \frac{\pi}{2^{1011}}

\frac{(2022) !}{(1011) ! 2^{2022}} \pi

AP EAPCET 07-Jul-2022 Shift 1 Paper

Section: Mathematics

Question : 77 of 160

Marks: +1, -0

∫

−π

‌

cos2022x

1+(2022)x

dx=

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