1.8g of glucose (molar mass 180gmol−1 ) is dissolved in 0.1kg of water. The freezing point of the solution ( in ‌∘C ) is (Kf‌ for water ‌=1.86Kkgmol−1)
Depression in freezing point is given as ∆T=iKf×m where, i= van't Hoff factor Kf= molal freezing point depression constant m=molality Molar mass of glucose (C6H12O6) =12×6+12×1+6×16=180g∕mol Molality of glucose =‌