AP EAPCET 07-Jul-2022 Shift 1 Paper

Bond order is the number of chemical bonds present between two atoms of a molecule.
Bond order (BO)=
No. of bonding orbital electrons

−No.of‌non−bonding‌orbital‌electrons

2

I. N2=σls2,σ*1s2,σ2s2,σ*2s2,π2px2=π2py2,σ2pz2 Bond order =

10−4

2

=3
II. O2=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2 ≈2py2,π*2pxI≈π*2py1 Bond order =

10−6

2

=2
III. O2+=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2π2py2, π*2px1 Bond order =

10−5

2

=2.5
IV. O2−=σl˙s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2π2py2 π*2px2≈π*2py1
Bond order =

10−7

2

=1.5
Hence, bond order can be arranged as I > III > II > IV