AP EAPCET 06-Jul-2022 Shift 2 Paper

Given, W=200J
Since, ideal monoatomic gas expands at constant pressure, hence heat absorbed, Q=nCp∆T Work done, W=nR∆T
Work done,W=nR∆T
‌‌

Q

W

=‌

nCp∆T

nR∆T

‌‌

Q

W

=‌

Cp

R

......(i)
for monoatomic gas, CV=1.5R
Cp‌=CV+R
‌=1.5R+R
⇒‌‌Cp=2.5R......(ii)
From Eqs (i) and (ii), we get .
‌

Q

W

‌=‌

2.5R

R

‌=2.5
Q‌‌=2.5W
‌=25×200
‌=500J