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Question : 71 of 160
Marks:
+1,
-0
Solution:
Let
I=∫‌| cos4x |
| (sin‌2x+sin‌−3xcos5x)3 |
‌dx ‌=∫‌| cos4x |
| (sin‌2x)3(1+cot5⋅x)3 |
‌=∫‌‌dx⇒1+cot5x=y ‌⇒‌‌5cot4x(−cosec2x)‌dx=dy‌⇒cot4xcosec2x‌dx=‌dy I‌=‌‌∫‌dy=‌‌‌=‌×y−2+C‌=‌[1+cot5x]−2+C
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