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Question : 59 of 160
Marks:
+1,
-0
Solution:
‌(r2+‌) =‌[‌] =‌[‌| (r+)−(r−) |
| 1+(r+‌)(r−‌) |
] =‌| −1 |
| ∑ |
| r=1n[tan−1(r+‌)−tan |
(r−‌)] [∵tan−1(a−b)=tan−1[‌]] ‌=[tan−1(n+‌)−tan−1(‌)]‌=[tan−1(n+‌)−tan−1(‌)]‌=tan−1∞−tan−1‌=‌−tan−1‌‌=cot−1‌=tan−12
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