In a \triangle A B C,|\overline{C B}|=\overline{a},|\overrightarrow{C A}|=\overline{b},|\overrightarrow{A B}|=\overline{c} and C D is the median through the vertex C. Then \overline{C A} \cdot \overline{C D}=

Correct Answer is : 14(a2+3b2−c2)

\frac{1}{4}(3 a^{2}+b^{2}-c^{2})

\frac{1}{4}(a^{2}+3 b^{2}-c^{2})

\frac{1}{4}(a^{2}+b^{2}-3 c^{2})

\frac{1}{4}(-3 a^{2}-b^{2}+c^{2})

AP EAPCET 06-Jul-2022 Shift 2 Paper

Section: Mathematics

Question : 31 of 160

Marks: +1, -0

In a △ABC,|CB|=a,|

→

|=b,|

→

|=c and CD is the median through the vertex C. Then CA⋅CD=

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