AP EAPCET 06-Jul-2022 Shift 2 Paper

Given, C1‌=10µF
‌=10−5F
V1‌=9VCharge on capacitor C1,
q1‌=C1V1
‌=9×10−5C
C2‌=20µF=2×10−5F
when uncharged capacitor C2 is connected with charged capacitor C1, then charges will flow from capacitor C1 to C2 till both gain the same potential i.e common potential.
Common potential, V=‌

‌ total charge ‌

‌ total capacitance ‌

‌=‌

q1

C1+C2

=‌

9×10−5

10−5+2×10−5

‌=‌

9×10−5

3×10−5

=3V
Charge on capacitor C2,q2=C2V
=2×10−5×3=6×10−5C